Integrand size = 18, antiderivative size = 93 \[ \int \frac {\text {arctanh}(a x)^3}{x (c+a c x)} \, dx=\frac {\text {arctanh}(a x)^3 \log \left (2-\frac {2}{1+a x}\right )}{c}-\frac {3 \text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,-1+\frac {2}{1+a x}\right )}{2 c}-\frac {3 \text {arctanh}(a x) \operatorname {PolyLog}\left (3,-1+\frac {2}{1+a x}\right )}{2 c}-\frac {3 \operatorname {PolyLog}\left (4,-1+\frac {2}{1+a x}\right )}{4 c} \]
arctanh(a*x)^3*ln(2-2/(a*x+1))/c-3/2*arctanh(a*x)^2*polylog(2,-1+2/(a*x+1) )/c-3/2*arctanh(a*x)*polylog(3,-1+2/(a*x+1))/c-3/4*polylog(4,-1+2/(a*x+1)) /c
Time = 0.75 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.92 \[ \int \frac {\text {arctanh}(a x)^3}{x (c+a c x)} \, dx=\frac {\pi ^4-32 \text {arctanh}(a x)^4+64 \text {arctanh}(a x)^3 \log \left (1-e^{2 \text {arctanh}(a x)}\right )+96 \text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,e^{2 \text {arctanh}(a x)}\right )-96 \text {arctanh}(a x) \operatorname {PolyLog}\left (3,e^{2 \text {arctanh}(a x)}\right )+48 \operatorname {PolyLog}\left (4,e^{2 \text {arctanh}(a x)}\right )}{64 c} \]
(Pi^4 - 32*ArcTanh[a*x]^4 + 64*ArcTanh[a*x]^3*Log[1 - E^(2*ArcTanh[a*x])] + 96*ArcTanh[a*x]^2*PolyLog[2, E^(2*ArcTanh[a*x])] - 96*ArcTanh[a*x]*PolyL og[3, E^(2*ArcTanh[a*x])] + 48*PolyLog[4, E^(2*ArcTanh[a*x])])/(64*c)
Time = 0.63 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.08, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {6494, 6618, 6622, 7164}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\text {arctanh}(a x)^3}{x (a c x+c)} \, dx\) |
\(\Big \downarrow \) 6494 |
\(\displaystyle \frac {\text {arctanh}(a x)^3 \log \left (2-\frac {2}{a x+1}\right )}{c}-\frac {3 a \int \frac {\text {arctanh}(a x)^2 \log \left (2-\frac {2}{a x+1}\right )}{1-a^2 x^2}dx}{c}\) |
\(\Big \downarrow \) 6618 |
\(\displaystyle \frac {\text {arctanh}(a x)^3 \log \left (2-\frac {2}{a x+1}\right )}{c}-\frac {3 a \left (\frac {\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,\frac {2}{a x+1}-1\right )}{2 a}-\int \frac {\text {arctanh}(a x) \operatorname {PolyLog}\left (2,\frac {2}{a x+1}-1\right )}{1-a^2 x^2}dx\right )}{c}\) |
\(\Big \downarrow \) 6622 |
\(\displaystyle \frac {\text {arctanh}(a x)^3 \log \left (2-\frac {2}{a x+1}\right )}{c}-\frac {3 a \left (-\frac {1}{2} \int \frac {\operatorname {PolyLog}\left (3,\frac {2}{a x+1}-1\right )}{1-a^2 x^2}dx+\frac {\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,\frac {2}{a x+1}-1\right )}{2 a}+\frac {\text {arctanh}(a x) \operatorname {PolyLog}\left (3,\frac {2}{a x+1}-1\right )}{2 a}\right )}{c}\) |
\(\Big \downarrow \) 7164 |
\(\displaystyle \frac {\text {arctanh}(a x)^3 \log \left (2-\frac {2}{a x+1}\right )}{c}-\frac {3 a \left (\frac {\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,\frac {2}{a x+1}-1\right )}{2 a}+\frac {\text {arctanh}(a x) \operatorname {PolyLog}\left (3,\frac {2}{a x+1}-1\right )}{2 a}+\frac {\operatorname {PolyLog}\left (4,\frac {2}{a x+1}-1\right )}{4 a}\right )}{c}\) |
(ArcTanh[a*x]^3*Log[2 - 2/(1 + a*x)])/c - (3*a*((ArcTanh[a*x]^2*PolyLog[2, -1 + 2/(1 + a*x)])/(2*a) + (ArcTanh[a*x]*PolyLog[3, -1 + 2/(1 + a*x)])/(2 *a) + PolyLog[4, -1 + 2/(1 + a*x)]/(4*a)))/c
3.2.30.3.1 Defintions of rubi rules used
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_))), x _Symbol] :> Simp[(a + b*ArcTanh[c*x])^p*(Log[2 - 2/(1 + e*(x/d))]/d), x] - Simp[b*c*(p/d) Int[(a + b*ArcTanh[c*x])^(p - 1)*(Log[2 - 2/(1 + e*(x/d))] /(1 - c^2*x^2)), x], x] /; FreeQ[{a, b, c, d, e}, x] && IGtQ[p, 0] && EqQ[c ^2*d^2 - e^2, 0]
Int[(Log[u_]*((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.))/((d_) + (e_.)*(x_)^ 2), x_Symbol] :> Simp[(a + b*ArcTanh[c*x])^p*(PolyLog[2, 1 - u]/(2*c*d)), x ] - Simp[b*(p/2) Int[(a + b*ArcTanh[c*x])^(p - 1)*(PolyLog[2, 1 - u]/(d + e*x^2)), x], x] /; FreeQ[{a, b, c, d, e}, x] && IGtQ[p, 0] && EqQ[c^2*d + e, 0] && EqQ[(1 - u)^2 - (1 - 2/(1 + c*x))^2, 0]
Int[(((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*PolyLog[k_, u_])/((d_) + (e_ .)*(x_)^2), x_Symbol] :> Simp[(-(a + b*ArcTanh[c*x])^p)*(PolyLog[k + 1, u]/ (2*c*d)), x] + Simp[b*(p/2) Int[(a + b*ArcTanh[c*x])^(p - 1)*(PolyLog[k + 1, u]/(d + e*x^2)), x], x] /; FreeQ[{a, b, c, d, e, k}, x] && IGtQ[p, 0] & & EqQ[c^2*d + e, 0] && EqQ[u^2 - (1 - 2/(1 + c*x))^2, 0]
Int[(u_)*PolyLog[n_, v_], x_Symbol] :> With[{w = DerivativeDivides[v, u*v, x]}, Simp[w*PolyLog[n + 1, v], x] /; !FalseQ[w]] /; FreeQ[n, x]
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 3.38 (sec) , antiderivative size = 1094, normalized size of antiderivative = 11.76
method | result | size |
derivativedivides | \(\text {Expression too large to display}\) | \(1094\) |
default | \(\text {Expression too large to display}\) | \(1094\) |
parts | \(\text {Expression too large to display}\) | \(1481\) |
1/c*arctanh(a*x)^3*ln(a*x)-1/c*arctanh(a*x)^3*ln(a*x+1)-3/c*(-2/3*arctanh( a*x)^3*ln((a*x+1)/(-a^2*x^2+1)^(1/2))+1/6*arctanh(a*x)^4+1/3*arctanh(a*x)^ 3*ln((a*x+1)^2/(-a^2*x^2+1)-1)-1/3*arctanh(a*x)^3*ln(1+(a*x+1)/(-a^2*x^2+1 )^(1/2))-arctanh(a*x)^2*polylog(2,-(a*x+1)/(-a^2*x^2+1)^(1/2))+2*arctanh(a *x)*polylog(3,-(a*x+1)/(-a^2*x^2+1)^(1/2))-2*polylog(4,-(a*x+1)/(-a^2*x^2+ 1)^(1/2))-1/3*arctanh(a*x)^3*ln(1-(a*x+1)/(-a^2*x^2+1)^(1/2))-arctanh(a*x) ^2*polylog(2,(a*x+1)/(-a^2*x^2+1)^(1/2))+2*arctanh(a*x)*polylog(3,(a*x+1)/ (-a^2*x^2+1)^(1/2))-2*polylog(4,(a*x+1)/(-a^2*x^2+1)^(1/2))-1/6*(I*Pi*csgn (I*(-(a*x+1)^2/(a^2*x^2-1)-1))*csgn(I/(-(a*x+1)^2/(a^2*x^2-1)+1))*csgn(I*( -(a*x+1)^2/(a^2*x^2-1)-1)/(-(a*x+1)^2/(a^2*x^2-1)+1))-I*Pi*csgn(I/(-(a*x+1 )^2/(a^2*x^2-1)+1))*csgn(I*(-(a*x+1)^2/(a^2*x^2-1)-1)/(-(a*x+1)^2/(a^2*x^2 -1)+1))^2+I*Pi*csgn(I/(-(a*x+1)^2/(a^2*x^2-1)+1))*csgn(I*(a*x+1)^2/(a^2*x^ 2-1)/(-(a*x+1)^2/(a^2*x^2-1)+1))^2-I*Pi*csgn(I/(-(a*x+1)^2/(a^2*x^2-1)+1)) *csgn(I*(a*x+1)^2/(a^2*x^2-1))*csgn(I*(a*x+1)^2/(a^2*x^2-1)/(-(a*x+1)^2/(a ^2*x^2-1)+1))-I*Pi*csgn(I*(-(a*x+1)^2/(a^2*x^2-1)-1))*csgn(I*(-(a*x+1)^2/( a^2*x^2-1)-1)/(-(a*x+1)^2/(a^2*x^2-1)+1))^2+I*Pi*csgn(I*(-(a*x+1)^2/(a^2*x ^2-1)-1)/(-(a*x+1)^2/(a^2*x^2-1)+1))^3+I*Pi*csgn(I*(a*x+1)^2/(a^2*x^2-1)/( -(a*x+1)^2/(a^2*x^2-1)+1))^3-I*Pi*csgn(I*(a*x+1)^2/(a^2*x^2-1))*csgn(I*(a* x+1)^2/(a^2*x^2-1)/(-(a*x+1)^2/(a^2*x^2-1)+1))^2+I*Pi*csgn(I*(a*x+1)/(-a^2 *x^2+1)^(1/2))^2*csgn(I*(a*x+1)^2/(a^2*x^2-1))+2*I*Pi*csgn(I*(a*x+1)/(-...
\[ \int \frac {\text {arctanh}(a x)^3}{x (c+a c x)} \, dx=\int { \frac {\operatorname {artanh}\left (a x\right )^{3}}{{\left (a c x + c\right )} x} \,d x } \]
\[ \int \frac {\text {arctanh}(a x)^3}{x (c+a c x)} \, dx=\frac {\int \frac {\operatorname {atanh}^{3}{\left (a x \right )}}{a x^{2} + x}\, dx}{c} \]
\[ \int \frac {\text {arctanh}(a x)^3}{x (c+a c x)} \, dx=\int { \frac {\operatorname {artanh}\left (a x\right )^{3}}{{\left (a c x + c\right )} x} \,d x } \]
1/8*log(a*x + 1)*log(-a*x + 1)^3/c - 1/8*integrate(-((a*x - 1)*log(a*x + 1 )^3 - 3*(a*x - 1)*log(a*x + 1)^2*log(-a*x + 1) - 3*(a^2*x^2 + 1)*log(a*x + 1)*log(-a*x + 1)^2)/(a^2*c*x^3 - c*x), x)
\[ \int \frac {\text {arctanh}(a x)^3}{x (c+a c x)} \, dx=\int { \frac {\operatorname {artanh}\left (a x\right )^{3}}{{\left (a c x + c\right )} x} \,d x } \]
Timed out. \[ \int \frac {\text {arctanh}(a x)^3}{x (c+a c x)} \, dx=\int \frac {{\mathrm {atanh}\left (a\,x\right )}^3}{x\,\left (c+a\,c\,x\right )} \,d x \]